If the angle of bank is increased from 60° to 80°, how much would the load factor increase?

If the angle of bank is increased from 60° to 80°, how much would the load factor increase?

• A. 2 Gs
• B. 3 Gs
• C. 4 Gs
• D. 5 Gs

Answer: (C)

To determine how the load factor increases when the angle of bank is increased from 60° to 80°, it is important to understand the relationship between bank angle and load factor in turning flight. Load factor (often represented as 'G's) is influenced by the angle of bank; it can be calculated using the formula: \[ \text{Load Factor} = \frac{1}{\cos(\theta)} \] where θ is the bank angle. This means that as the bank angle increases, the cosine of that angle decreases, resulting in an increase in load factor. For a bank angle of 60°, the load factor would be: \[ \text{Load Factor at 60°} = \frac{1}{\cos(60°)} = \frac{1}{0.5} = 2 \text{ Gs} \] For a bank angle of 80°, the load factor would be: \[ \text{Load Factor at 80°} = \frac{1}{\cos(80°)} \approx \frac{1}{0.1736} \approx 5.76 \text{ Gs} \] To find the increase in the load factor, you subtract the

To determine how the load factor increases when the angle of bank is increased from 60° to 80°, it is important to understand the relationship between bank angle and load factor in turning flight.

Load factor (often represented as 'G's) is influenced by the angle of bank; it can be calculated using the formula:

[ \text{Load Factor} = \frac{1}{\cos(\theta)} ]

where θ is the bank angle. This means that as the bank angle increases, the cosine of that angle decreases, resulting in an increase in load factor.

For a bank angle of 60°, the load factor would be:

[ \text{Load Factor at 60°} = \frac{1}{\cos(60°)} = \frac{1}{0.5} = 2 \text{ Gs} ]

For a bank angle of 80°, the load factor would be:

[ \text{Load Factor at 80°} = \frac{1}{\cos(80°)} \approx \frac{1}{0.1736} \approx 5.76 \text{ Gs} ]

To find the increase in the load factor, you subtract the